12. Output devices¶
This week, as a group assignment, examine the power consumption of the circuit.
Research¶
The power consumption is obtained by the following formula. W = V × A
If power consumption is multiplied by time, it will become power consumption every hour. Wh = W × h
An example of power consumption in Japan. In Japan, the basic rate changes depending on the number of amps to be contracted.
| Amps | BasicRate |
|---|---|
| 10A | ¥280.80 |
| 15A | ¥421.20 |
| 20A | ¥561.60 |
| 30A | ¥842.40 |
| 40A | ¥1,123.20 |
| 50A | ¥1,404.00 |
| 60A | ¥1,684.80 |
And the rate of wattage per hour is changed in three steps
| kWh | Rate |
|---|---|
| 0 - 120 | ¥19.52 |
| 120 - 300 | ¥26.00 |
| 300- | ¥30.02 |
Useful links¶
Instruments¶
-
Output device
- Peltier Element
- Spec
- 12V
- 5A
- Internal resistance
- 2.4〜2.7Ω
- 12V / 2.5Ω = 4.8A ≠ 5A
-
Measuring tools
Check the power consumption by increasing 2V from 1V
- 0V
- 1V → 0.27A
- 3V → 0.75A
- 5V → 0.98A
- 7V → 1.40A
- Table
By measuring the temperature, I was thinking about examining the relationship between power consumption and temperature.
However, when the measurement took time, the temperature rose during that time.
As a result, at 7 V, the Peltier element was destroyed and no current flowed.
Power consumption of Peltier device (TEC-12705)¶
Power consumption and charge for 1 hour at each voltage
| Voltage | Ampere | Killo Watt per Hour | Charge |
|---|---|---|---|
| 1V | 0.27A | 0.00027kWh | ¥0.00527 |
| 3V | 0.75A | 0.00225kWh | ¥0.0585 |
| 5V | 0.98A | 0.0049kWh | ¥0.095648 |
| 7V | 1.40A | 0.0098kWh | ¥0.191296 |